Table of contents

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1. Chemical Measurements1h 50m
2. Tools of the Trade1h 17m
3. Experimental Error1h 52m
4 & 5. Statistics, Quality Assurance and Calibration Methods1h 57m
6. Chemical Equilibrium3h 41m
7. Activity and the Systematic Treatment of Equilibrium1h 0m
8. Monoprotic Acid-Base Equilibria1h 53m
9. Polyprotic Acid-Base Equilibria2h 17m
10. Acid-Base Titrations2h 37m
11. EDTA Titrations1h 34m
12. Advanced Topics in Equilibrium1h 16m
13. Fundamentals of Electrochemistry2h 19m
14. Electrodes and Potentiometry41m
15. Redox Titrations1h 14m
16. Electroanalytical Techniques57m
17. Fundamentals of Spectrophotometry50m

1. Chemical Measurements

Chemical Concentrations

Analytical Chemistry

1. Chemical Measurements

Chemical Concentrations

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Multiple Choice

Which of the following best describes the initial concentration (m) of sodium thiocyanate in a reaction mixture if 0.10 mol of NaSCN is dissolved in 1.0 L of solution?

1.0 M

0.010 M

10 M

0.10 M

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Verified step by step guidance

Step 1: Understand the concept of molarity (M), which is defined as the number of moles of solute divided by the volume of solution in liters. The formula for molarity is:

M = \frac{n}{V}

, where

n

is the number of moles of solute and

V

is the volume of solution in liters.

Step 2: Identify the given values in the problem. The number of moles of sodium thiocyanate (

n

) is 0.10 mol, and the volume of the solution (

V

) is 1.0 L.

Step 3: Substitute the given values into the molarity formula:

M = \frac{0.10}{1.0}

Step 4: Simplify the expression to calculate the molarity. Since the numerator and denominator are straightforward, the division will yield the molarity value.

Step 5: Interpret the result. The calculated molarity represents the initial concentration of sodium thiocyanate in the solution, which corresponds to one of the provided answer choices.