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Multiple Choice
In UV-Vis spectrophotometry, absorbance is defined as , where is the fraction transmittance. Which expression correctly gives percent transmittance () from absorbance ?
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Recall the definition of absorbance in UV-Vis spectrophotometry: \(A = -\log_{10}(T)\), where \(T\) is the fraction transmittance (a value between 0 and 1).
To find the fraction transmittance \(T\) from absorbance \(A\), rearrange the equation by taking the inverse logarithm (antilog) of both sides: \(T = 10^{-A}\).
Percent transmittance (%T) is the fraction transmittance multiplied by 100 to convert it into a percentage: \(\%T = 100 \times T\).
Substitute the expression for \(T\) into the percent transmittance formula: \(\%T = 100 \times 10^{-A}\).
Thus, the correct expression for percent transmittance in terms of absorbance is \(\%T = 100 \times 10^{-A}\).