Table of contents
- 1. Chemical Measurements1h 50m
- 2. Tools of the Trade1h 17m
- 3. Experimental Error1h 52m
- 4 & 5. Statistics, Quality Assurance and Calibration Methods1h 57m
- 6. Chemical Equilibrium3h 41m
- 7. Activity and the Systematic Treatment of Equilibrium1h 0m
- 8. Monoprotic Acid-Base Equilibria1h 53m
- 9. Polyprotic Acid-Base Equilibria2h 17m
- 10. Acid-Base Titrations2h 37m
- 11. EDTA Titrations1h 34m
- 12. Advanced Topics in Equilibrium1h 16m
- 13. Fundamentals of Electrochemistry2h 19m
- 14. Electrodes and Potentiometry41m
- 15. Redox Titrations1h 14m
- 16. Electroanalytical Techniques57m
- 17. Fundamentals of Spectrophotometry50m
7. Activity and the Systematic Treatment of Equilibrium
Ionic Strength of Soluble Salts
Multiple Choice
Calculate the ionic strength for the following ionic compound.
0.04 M SnO2
A
0.40
B
0.48
C
0.12
D
0.96
E
0.24
1 Comment
Verified step by step guidance1
Identify the ions present in the compound SnO2. Tin(IV) oxide dissociates into Sn^{4+} and O^{2-} ions in solution.
Determine the concentration of each ion in the solution. Given that the concentration of SnO2 is 0.04 M, the concentration of Sn^{4+} ions is 0.04 M, and the concentration of O^{2-} ions is 0.08 M (since each SnO2 produces two O^{2-} ions).
Use the formula for ionic strength: I = \(\frac{1}{2}\) \(\sum\) c_i z_i^2, where c_i is the concentration of each ion and z_i is the charge of each ion.
Substitute the concentrations and charges into the formula: I = \(\frac{1}{2}\) [(0.04)(4)^2 + (0.08)(2)^2].
Calculate the ionic strength by evaluating the expression, ensuring to square the charges and multiply by the respective concentrations before summing and dividing by 2.

