Table of contents

1. Introduction to Anatomy & Physiology5h 43m
2. Cell Chemistry & Cell Components12h 36m
3. Energy & Cell Processes10h 6m
4. Tissues & Histology10h 3m
5. Integumentary System2h 20m
6. Bones & Skeletal Tissue2h 16m
7. The Skeletal System2h 35m
8. Joints2h 17m
9. Muscle Tissue2h 33m
10. Muscles1h 11m
11. Nervous Tissue and Nervous System1h 35m
12. The Central Nervous System1h 6m
- Introduction to the Central Nervous System
  18m
- The Cerebrum
  48m
13. The Peripheral Nervous System1h 26m
14. The Autonomic Nervous System1h 38m
15. The Special Senses2h 41m
16. The Endocrine System2h 48m
17. The Blood3h 22m
18. The Heart3h 42m
19. The Blood Vessels3h 35m
20. The Lymphatic System3h 16m
21. The Immune System14h 37m
22. The Respiratory System3h 20m
23. The Digestive System2h 5m
24. Metabolism and Nutrition4h 0m
25. The Urinary System2h 39m
26. Fluid and Electrolyte Balance, Acid Base Balance37m
27. The Reproductive System2h 5m
28. Human Development1h 21m
29. Heredity3h 32m

2. Cell Chemistry & Cell Components

Hydrogen Bonding

Anatomy & Physiology

2. Cell Chemistry & Cell Components

Hydrogen Bonding

Previous problemNext problem

4:04 minutes

Problem 6

Textbook Question

Locate fluorine (F) on the partial periodic table provided in Figure 2.2. Predict its relative electronegativity compared to hydrogen, sodium, and oxygen. State the number and type of bond(s) you expect it would form if it reacted with sodium (Na).

Verified step by step guidance

Locate fluorine (F) on the partial periodic table provided in Figure 2.2. It is in the second row, seventh column.

Compare the position of fluorine (F) with hydrogen (H), sodium (Na), and oxygen (O) on the periodic table. Fluorine is to the right of hydrogen and sodium, and to the right of oxygen.

Recall that electronegativity increases across a period (left to right) and decreases down a group (top to bottom) on the periodic table. Therefore, fluorine has a higher electronegativity than hydrogen, sodium, and oxygen.

Predict the type of bond fluorine would form with sodium (Na). Sodium is a metal and fluorine is a non-metal, so they would form an ionic bond.

State the number and type of bond(s) expected if fluorine reacts with sodium. Sodium (Na) would lose one electron to form Na+, and fluorine (F) would gain one electron to form F-, resulting in one ionic bond between Na+ and F-.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above

Video duration:

Play a video:

Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electronegativity

Electronegativity is a measure of an atom's ability to attract and hold onto electrons when forming chemical bonds. It is a key factor in determining how atoms interact with each other. In the periodic table, electronegativity generally increases across a period from left to right and decreases down a group. Fluorine, being in the top right corner of the periodic table, is the most electronegative element.

Chemical Bonding

Chemical bonding refers to the forces that hold atoms together in compounds. The main types of bonds are ionic, covalent, and metallic. When sodium (Na) reacts with fluorine (F), an ionic bond is expected to form due to the transfer of an electron from sodium to fluorine, resulting in the formation of Na+ and F- ions. Understanding the type of bond helps predict the properties of the resulting compound.

Periodic Trends

Periodic trends are patterns observed in the periodic table that illustrate how certain properties of elements change across periods and down groups. These trends include atomic radius, ionization energy, and electronegativity. Recognizing these trends is essential for predicting the behavior of elements, such as the relative electronegativity of fluorine compared to hydrogen, sodium, and oxygen, which influences their bonding characteristics.