Table of contents

1. Introduction to Biochemistry4h 34m
2. Water3h 23m
3. Amino Acids8h 10m
4. Protein Structure10h 4m
5. Protein Techniques14h 5m
6. Enzymes and Enzyme Kinetics13h 38m
7. Enzyme Inhibition and Regulation 8h 42m
8. Protein Function 9h 41m
9. Carbohydrates7h 49m
10. Lipids5h 49m
11. Biological Membranes and Transport 6h 37m
12. Biosignaling9h 45m
Review 1: Nucleic Acids, Lipids, & Membranes2h 47m
Review 2: Biosignaling, Glycolysis, Gluconeogenesis, & PP-Pathway3h 12m
Review 3: Pyruvate & Fatty Acid Oxidation, Citric Acid Cycle, & Glycogen Metabolism2h 26m
Review 4: Amino Acid Oxidation, Oxidative Phosphorylation, & Photophosphorylation1h 48m

2. Water

Henderson Hasselbalch Equation

Biochemistry

2. Water

Henderson Hasselbalch Equation

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Multiple Choice

Consider 100 mL of a 1M acid solution (pK _a = 7.4) at pH = 8. Calculate final pH if 30 mL of 1M HCl is added.

pH = 7.4

pH = 7.9

pH = 7.1

pH = 8.2

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Verified step by step guidance

Identify the initial conditions: You have 100 mL of a 1M acid solution with a pKa of 7.4 and an initial pH of 8.0.

Determine the moles of acid and base present initially: Since the solution is at pH 8, which is above the pKa, the solution is more in the deprotonated (A-) form. Use the Henderson-Hasselbalch equation to find the ratio of [A-] to [HA].

Calculate the moles of HCl added: 30 mL of 1M HCl corresponds to 0.03 moles of HCl. This will react with the deprotonated form (A-) of the acid.

Adjust the moles of A- and HA: The added HCl will convert some of the A- back to HA. Subtract the moles of HCl from A- and add them to HA.

Recalculate the pH using the Henderson-Hasselbalch equation: With the new concentrations of HA and A-, use the equation pH = pKa + log([A-]/[HA]) to find the new pH of the solution.