Given the equation below, find when and .
Table of contents
- 0. Functions4h 53m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation2h 18m
- 4. Derivatives of Exponential & Logarithmic Functions1h 16m
- 5. Applications of Derivatives2h 19m
- 6. Graphical Applications of Derivatives6h 0m
- 7. Antiderivatives & Indefinite Integrals48m
- 8. Definite Integrals4h 36m
- 9. Graphical Applications of Integrals1h 43m
- 10. Integrals of Inverse, Exponential, & Logarithmic Functions21m
- 11. Techniques of Integration2h 7m
- 12. Trigonometric Functions6h 54m
- Angles29m
- Trigonometric Functions on Right Triangles1h 8m
- Solving Right Triangles23m
- Trigonometric Functions on the Unit Circle1h 19m
- Graphs of Sine & Cosine46m
- Graphs of Other Trigonometric Functions32m
- Trigonometric Identities52m
- Derivatives of Trig Functions42m
- Integrals of Basic Trig Functions28m
- Integrals of Other Trig Functions10m
- 13: Intro to Differential Equations2h 23m
- 14. Sequences & Series2h 8m
- 15. Power Series2h 19m
- 16. Probability & Calculus45m
5. Applications of Derivatives
Related Rates
Multiple Choice
Given the equation below, find dz/dt when dx/dt=3, dy/dt=2, x=2, y=4, and z=1.
x2+y2−3z2=125
A
314
B
316
C
−314
D
−316
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Verified step by step guidance1
Step 1: Start by identifying the given equation: x^2 + y^2 - 3z^2 = 125. This is the constraint that relates x, y, and z.
Step 2: Differentiate both sides of the equation with respect to t using implicit differentiation. Remember to apply the chain rule for each term. The derivative will be: 2x(dx/dt) + 2y(dy/dt) - 6z(dz/dt) = 0.
Step 3: Substitute the given values into the differentiated equation. These values are: dx/dt = 3, dy/dt = 2, x = 2, y = 4, and z = 1.
Step 4: Solve for dz/dt by isolating it in the equation. Rearrange the terms so that dz/dt is on one side of the equation, and all other terms are on the other side.
Step 5: Simplify the resulting expression to find dz/dt. This will give you the rate of change of z with respect to t.
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