Find the domain of the rational function. Then, write it in lowest terms.f(x)=x2+9x−3f\left(x\right)=\frac{x^2+9}{x-3}f(x)=x−3x2+9

{x∣x≠3}, f(x)=x2+9x−3f\left(x\right)=\frac{$$x^2+9$$}{x-3}f(x)=x−3x2+9

Find the domain of the rational function. Then, write it in lowest terms. f ( x ) = x 2 + 9 x − 3 f\left(x\right)=\frac{x^2+9}{x-3} f ( x ) = x − 3 x 2 + 9

Hey, everyone. Let's take a look at this practice problem. Here, we want to find the domain of the rational function and then write it in lowest terms. So let's go ahead and start by finding the domain. Now when we find the domain, we want to take our denominator and set it equal to 0. So here doing that, I can go ahead and solve for x by simply adding 3 to both sides. Now that will cancel over here, leaving me with x is equal to 3, and this represents my domain restriction. So I know that my domain is now x such that x cannot be equal to 3 because that would make my denominator 0. So this is our domain. Let's go ahead and write this in lowest terms. So taking another look at my function here, f of x is equal to x squared plus 9 divided by x minus 3. Remember, we want to fully factor both the top and the bottom of our fraction. But looking at the top here, x squared plus 9 is actually not going to factor any further. It's just going to remain x squared plus 9. Now our denominator also cannot be factored any further. It's just x minus 3. So this is actually actually already in lowest terms, x squared plus 9 divided by x minus 3. So I don't need to do anything. I don't need to cancel anything out with my function, and this is my function in lowest terms. Thanks for watching, and I'll see you in the next video.

Find the domain of the rational function. Then, write it in lowest terms.f(x)=x2+9x−3f\left(x\right)=\frac{$$x^2+9$$}{x-3}f(x)=x−3x2+9

{x∣x≠3}, f(x)=x2+9x−3f\left(x\right)=\frac{$$x^2+9$$}{x-3}f(x)=x−3x2+9

{x∣x≠0}, f(x)=1x−3f\left(x\right)=\frac{1}{x-3}f(x)=x−31

{x∣x≠−3}, f(x)=x2+9x−3f\left(x\right)=\frac{$$x^2+9$$}{x-3}f(x)=x−3x2+9

{x∣x≠3}, f(x)=x+3f\left(x\right)=x+3f(x)=x+3

0. Functions

Common Functions

Business Calculus

0. Functions

Common Functions

Struggling with Business Calculus?

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Multiple Choice

Find the domain of the rational function. Then, write it in lowest terms.
$f$\left$(x$\right$)=$\frac{x^2+9}{x-3}$$

{x∣x≠0}, $f$\left$(x$\right$)=$\frac{1}{x-3}$$

{x∣x≠3}, $f$\left$(x$\right$)=$\frac{x^2+9}{x-3}$$

{x∣x≠−3}, $f$\left$(x$\right$)=$\frac{x^2+9}{x-3}$$

{x∣x≠3}, $f$\left$(x$\right$)=x+3$

Verified step by step guidance

Step 1: Identify the given rational function. The function is f(x) = (x^2 + 9) / (x - 3). A rational function is undefined when its denominator equals zero, so we need to find the values of x that make the denominator zero.

Step 2: Set the denominator equal to zero and solve for x. The denominator is (x - 3). Solve the equation x - 3 = 0 to find the value of x that makes the denominator undefined.

Step 3: Exclude the value of x that makes the denominator zero from the domain. Since x = 3 makes the denominator zero, the domain of the function is all real numbers except x = 3. In set notation, this is written as {x | x ≠ 3}.

Step 4: Simplify the rational function if possible. Check if the numerator (x^2 + 9) and the denominator (x - 3) have any common factors. In this case, they do not, so the function remains as f(x) = (x^2 + 9) / (x - 3).

Step 5: Verify the simplified function and domain. The function is f(x) = (x^2 + 9) / (x - 3), and the domain is {x | x ≠ 3}. This ensures the function is defined for all other values of x.

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Struggling with Business Calculus?

Find the domain of the rational function. Then, write it in lowest terms.f(x)=x2+9x−3f\(\left\)(x\(\right\))=\(\frac{x^2+9}{x-3}\)f(x)=x−3x2+9

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Find the domain of the rational function. Then, write it in lowest terms.
$f\(\left\)(x\(\right\))=\(\frac{x^2+9}{x-3}\)$