Common Functions: Videos & Practice Problems

Oil is introduced to a cylindrical vessel until it reaches a depth of $36$ ft. The cross-sectional area of the vessel is $15$ ft². A drain with an area of $2$ ft² located at the bottom of the vessel is opened at $t=0$ s. At time $t\ge 0$, the depth of the oil is represented by the function $d\left(t\right)={(6-0.13t)}^2$. Does this function provide a depth of $36$ ft as specified at $t=0$ s?