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Multiple Choice
A company wants to estimate the average time employees spend on a training module. 15 employees are randomly selected, & their completion times recorded. The sample of times to complete the module is normally distributed with mean 42.7 min & std. dev. 5.4 min. (B) Should management be concerned that the training might take too long if their policy states the module should take at most 45 min? Justify your answer using your confidence interval.
A
Yes
B
No
C
More information is needed.
Verified step by step guidance
1
Step 1: Identify the key components of the problem. The sample mean is 42.7 minutes, the sample standard deviation is 5.4 minutes, and the sample size is 15. The goal is to determine whether the training module completion time exceeds the policy limit of 45 minutes using a confidence interval.
Step 2: Recall the formula for the confidence interval for the mean when the sample is normally distributed: CI = x̄ ± z * (σ / √n), where x̄ is the sample mean, σ is the standard deviation, n is the sample size, and z is the z-score corresponding to the desired confidence level.
Step 3: Determine the confidence level to use (e.g., 95% confidence level is common in business statistics). Find the z-score associated with this confidence level using a z-table or statistical software. For a 95% confidence level, the z-score is approximately 1.96.
Step 4: Plug the values into the formula. Use x̄ = 42.7, σ = 5.4, n = 15, and z = 1.96 to calculate the margin of error: ME = z * (σ / √n). Then calculate the lower and upper bounds of the confidence interval: CI = [x̄ - ME, x̄ + ME].
Step 5: Compare the upper bound of the confidence interval to the policy limit of 45 minutes. If the upper bound exceeds 45 minutes, management should be concerned. If the upper bound is below 45 minutes, the training module completion time is within acceptable limits. If the upper bound is very close to 45 minutes, more information or a larger sample size may be needed to make a definitive conclusion.