A beverage company claims that on average, customers consume 500 mL of their new energy drink in a single sitting. To test this claim, a market researcher collects a random sample of 8 customers. Assume the sample is normal & make a 90% conf. int. for the true mean volume. Does the data support the company’s claim?
Table of contents
- 1. Introduction to Statistics53m
- 2. Describing Data with Tables and Graphs2h 1m
- 3. Describing Data Numerically1h 48m
- 4. Probability2h 26m
- 5. Binomial Distribution & Discrete Random Variables2h 55m
- 6. Normal Distribution & Continuous Random Variables1h 48m
- 7. Sampling Distributions & Confidence Intervals: Mean2h 8m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 20m
- 9. Hypothesis Testing for One Sample2h 23m
- 10. Hypothesis Testing for Two Samples3h 25m
- 11. Correlation1h 6m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 30m
- 14. ANOVA1h 4m
7. Sampling Distributions & Confidence Intervals: Mean
Confidence Intervals for Population Mean
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Find the critical value t2αfor an 80% confidence interval given a sample size of 51.
A
0.10
B
1.299
C
0.300
D
2.598

1
Understand that the critical value t_{\frac{\alpha}{2}} is used in constructing confidence intervals for the mean when the population standard deviation is unknown and the sample size is small.
Identify that the confidence level is 80%, which means the significance level \alpha is 0.20 (since \alpha = 1 - confidence level).
Calculate \frac{\alpha}{2} to find the tail probability for the t-distribution. For an 80% confidence interval, \frac{\alpha}{2} = 0.10.
Determine the degrees of freedom for the t-distribution, which is the sample size minus one. For a sample size of 51, the degrees of freedom is 50.
Use a t-distribution table or a statistical software to find the critical value t_{\frac{\alpha}{2}} for \frac{\alpha}{2} = 0.10 and 50 degrees of freedom.
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