Derivatives and tangent lines a. For the following functions and values of a, find f′(a). f(x) = x²; a=3
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Step 1: Understand the problem. We need to find the derivative of the function f(x) = x^2 and then evaluate it at a specific point, a = 3.
Step 2: Find the derivative of f(x) = x^2. The derivative, denoted as f'(x), is found using the power rule. The power rule states that if f(x) = x^n, then f'(x) = nx^(n-1).
Step 3: Apply the power rule to f(x) = x^2. Here, n = 2, so f'(x) = 2x^(2-1) = 2x.
Step 4: Evaluate the derivative at the given point a = 3. Substitute x = 3 into the derivative f'(x) = 2x to find f'(3).
Step 5: Simplify the expression obtained in Step 4 to find the value of f'(3).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivatives
A derivative represents the rate of change of a function with respect to its variable. It is defined as the limit of the average rate of change of the function as the interval approaches zero. In practical terms, the derivative at a point gives the slope of the tangent line to the function at that point.
A tangent line to a curve at a given point is a straight line that touches the curve at that point without crossing it. The slope of the tangent line is equal to the derivative of the function at that point. This concept is crucial for understanding how functions behave locally around specific values.
Function evaluation involves substituting a specific value into a function to determine its output. In the context of derivatives, evaluating the function at a point helps in calculating the derivative at that point. For example, to find f′(3) for f(x) = x², one must first understand how to compute f(3) and then apply the derivative formula.