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Multiple Choice
Given the implicit equation , find the value of the third derivative with respect to at the point where and .
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Verified step by step guidance
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Step 1: Start by differentiating the given implicit equation \(x^2 + xy + y^3 = 1\) with respect to \(x\). Use implicit differentiation, remembering that \(y\) is a function of \(x\). Apply the product rule to the term \(xy\) and the chain rule to \(y^3\).
Step 2: After differentiating, you will obtain an equation involving \(y'\) (the first derivative of \(y\) with respect to \(x\)). Solve this equation for \(y'\) at the given point \(x = 1\) and \(y = 0\). Substitute these values into the equation to find \(y'\).
Step 3: Differentiate the equation obtained in Step 2 again with respect to \(x\) to find \(y''\) (the second derivative of \(y\) with respect to \(x\)). Use implicit differentiation again, and substitute \(x = 1\), \(y = 0\), and \(y'\) (calculated in Step 2) into the resulting equation to find \(y''\).
Step 4: Differentiate the equation obtained in Step 3 one more time with respect to \(x\) to find \(y'''\) (the third derivative of \(y\) with respect to \(x\)). Use implicit differentiation, and substitute \(x = 1\), \(y = 0\), \(y'\), and \(y''\) (calculated in previous steps) into the resulting equation to find \(y'''\).
Step 5: Simplify the expression for \(y'''\) obtained in Step 4 to determine its value at \(x = 1\) and \(y = 0\). This will give you the final result for \(y'''\).