Consider the following graph of . Which of the following points are inflection points of ?
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
5. Graphical Applications of Derivatives
Finding Global Extrema
Multiple Choice
Let = on the interval . What is the maximum value of on this interval?
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Verified step by step guidance1
Step 1: Understand the problem. We are tasked with finding the maximum value of the function f(x) = x³ - 3x² + 4 on the interval [0, 3]. To do this, we need to evaluate the function at critical points and endpoints within the interval.
Step 2: Find the derivative of f(x) to locate critical points. The derivative f'(x) is calculated as follows: f'(x) = d/dx(x³ - 3x² + 4) = 3x² - 6x. This derivative will help us find where the slope of the function is zero (critical points).
Step 3: Solve f'(x) = 0 to find critical points. Set 3x² - 6x = 0 and factorize: 3x(x - 2) = 0. This gives x = 0 and x = 2 as critical points.
Step 4: Evaluate f(x) at the critical points and endpoints of the interval [0, 3]. The endpoints are x = 0 and x = 3, and the critical point within the interval is x = 2. Calculate f(0), f(2), and f(3) by substituting these values into f(x) = x³ - 3x² + 4.
Step 5: Compare the values of f(0), f(2), and f(3) to determine the maximum value. The largest value among these will be the maximum value of f(x) on the interval [0, 3].
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