For the function whose graph is given, which of the following best describes the domain of ?
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
0. Functions
Introduction to Functions
Multiple Choice
Evaluate the line integral of the vector field along the curve , where is the line segment from to . Which of the following is the value of the integral?
A
B
C
D
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Verified step by step guidance1
Step 1: Understand the problem. You are tasked with evaluating the line integral of the vector field F(x, y) = (x + 6y) dx + x^2 dy along the curve C, which is a line segment from (0, 0) to (2, 1). A line integral involves integrating a vector field along a given curve.
Step 2: Parameterize the curve C. Since C is a straight line segment from (0, 0) to (2, 1), you can parameterize it as r(t) = (2t, t), where t ranges from 0 to 1. Here, x = 2t and y = t.
Step 3: Compute dx and dy using the parameterization. From the parameterization r(t) = (2t, t), differentiate x and y with respect to t: dx = d(2t)/dt = 2 dt and dy = d(t)/dt = dt.
Step 4: Substitute the parameterization into the vector field F(x, y). Replace x with 2t and y with t in F(x, y): F(x, y) = (x + 6y) dx + x^2 dy becomes F(2t, t) = ((2t + 6t) * 2 dt) + (2t)^2 * dt.
Step 5: Set up the integral. Combine the terms and simplify the expression to set up the integral over t from 0 to 1. Evaluate the integral ∫[0 to 1] [(2t + 6t) * 2 + (2t)^2] dt. This will give the value of the line integral.
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