For the function whose graph is given, which of the following best describes the domain of ?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
0. Functions
Introduction to Functions
Struggling with Calculus?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Evaluate the line integral of the vector field along the curve , where is the line segment from to . Which of the following is the value of the integral?
A
B
C
D

1
Step 1: Understand the problem. You are tasked with evaluating the line integral of the vector field F(x, y) = (x + 6y) dx + x^2 dy along the curve C, which is a line segment from (0, 0) to (2, 1). A line integral involves integrating a vector field along a given curve.
Step 2: Parameterize the curve C. Since C is a straight line segment from (0, 0) to (2, 1), you can parameterize it as r(t) = (2t, t), where t ranges from 0 to 1. Here, x = 2t and y = t.
Step 3: Compute dx and dy using the parameterization. From the parameterization r(t) = (2t, t), differentiate x and y with respect to t: dx = d(2t)/dt = 2 dt and dy = d(t)/dt = dt.
Step 4: Substitute the parameterization into the vector field F(x, y). Replace x with 2t and y with t in F(x, y): F(x, y) = (x + 6y) dx + x^2 dy becomes F(2t, t) = ((2t + 6t) * 2 dt) + (2t)^2 * dt.
Step 5: Set up the integral. Combine the terms and simplify the expression to set up the integral over t from 0 to 1. Evaluate the integral ∫[0 to 1] [(2t + 6t) * 2 + (2t)^2] dt. This will give the value of the line integral.
Watch next
Master Introduction to Calculus Channel with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Multiple Choice
30
views
Introduction to Functions practice set
