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Multiple Choice
Given that and when , what is the value of when ?
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Verified step by step guidance
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Step 1: Recognize that the problem involves finding the value of x at a specific time t, given the derivative dx/dt = 4t^3 and an initial condition x = 5 when t = 1.
Step 2: To find x, integrate dx/dt = 4t^3 with respect to t. The integral of 4t^3 is ∫4t^3 dt = (4/4)t^4 = t^4 + C, where C is the constant of integration.
Step 3: Use the initial condition x = 5 when t = 1 to solve for the constant C. Substitute t = 1 and x = 5 into the equation x = t^4 + C to get 5 = 1^4 + C, which simplifies to C = 4.
Step 4: Substitute the value of C back into the equation for x to get x = t^4 + 4.
Step 5: To find the value of x when t = 2, substitute t = 2 into the equation x = t^4 + 4. This gives x = 2^4 + 4. Simplify the expression to find the value of x.