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Multiple Choice
For which values of is the function increasing?
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Verified step by step guidance
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Step 1: To determine where the function f(x) = (x^2 - 3)e^{-x} is increasing, calculate its derivative f'(x). Use the product rule since f(x) is the product of two functions: u(x) = x^2 - 3 and v(x) = e^{-x}. The product rule states: (uv)' = u'v + uv'.
Step 2: Compute the derivative of u(x) = x^2 - 3, which is u'(x) = 2x. Compute the derivative of v(x) = e^{-x}, which is v'(x) = -e^{-x}. Substitute these into the product rule formula to find f'(x).
Step 3: Combine the results to express f'(x): f'(x) = (2x)e^{-x} + (x^2 - 3)(-e^{-x}). Simplify the expression: f'(x) = e^{-x}(2x - x^2 + 3).
Step 4: Factorize the simplified derivative f'(x) = e^{-x}(3 - x^2 + 2x). Since e^{-x} is always positive for all x, the sign of f'(x) depends only on the quadratic expression (3 - x^2 + 2x). Rewrite it as: -x^2 + 2x + 3 = -(x^2 - 2x - 3). Factorize the quadratic: -(x - 3)(x + 1).
Step 5: Analyze the sign of -(x - 3)(x + 1). The function f(x) is increasing where f'(x) > 0. Solve the inequality -(x - 3)(x + 1) > 0 by testing intervals determined by the roots x = -1 and x = 3. Determine the intervals where the product is positive and conclude the values of x where f(x) is increasing.