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Multiple Choice
For the function , which ordered pair is closest to a local minimum of the function?
A
B
C
D
Verified step by step guidance
1
Step 1: Recognize that the problem involves finding the local minimum of the function f(x, y) = x^2 + y^2 - 4x - 6y + 13. To do this, we need to find the critical points by setting the partial derivatives of f(x, y) with respect to x and y equal to zero.
Step 2: Compute the partial derivative of f(x, y) with respect to x, denoted as ∂f/∂x. Using the power rule and derivative rules, we get ∂f/∂x = 2x - 4. Similarly, compute the partial derivative with respect to y, denoted as ∂f/∂y, which gives ∂f/∂y = 2y - 6.
Step 3: Set the partial derivatives equal to zero to find the critical points. Solve the equations 2x - 4 = 0 and 2y - 6 = 0. This will give the critical point (x, y).
Step 4: Verify that the critical point is a local minimum by using the second partial derivative test. Compute the second partial derivatives: f_xx = ∂²f/∂x² = 2, f_yy = ∂²f/∂y² = 2, and f_xy = ∂²f/∂x∂y = 0. Then calculate the determinant of the Hessian matrix, D = f_xx * f_yy - (f_xy)^2.
Step 5: If D > 0 and f_xx > 0, the critical point is a local minimum. Compare the critical point to the given options to determine which ordered pair is closest to the local minimum.