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Multiple Choice
Find the limit. limx→3x−2x2+2x−3
A
0
B
3
C
12
D
DNE
Verified step by step guidance
1
First, identify the type of limit problem. This is a rational function where both the numerator and the denominator are polynomials.
Check if direct substitution of x = 3 into the function results in an indeterminate form like 0/0. Substitute x = 3 into the numerator and denominator: \( x^2 + 2x - 3 \) becomes \( 3^2 + 2(3) - 3 \) and \( x - 2 \) becomes \( 3 - 2 \).
Calculate the values: The numerator becomes \( 9 + 6 - 3 = 12 \) and the denominator becomes \( 1 \). Since the denominator is not zero, the function is not indeterminate at x = 3.
Since the function is not indeterminate, the limit can be found by direct substitution. Substitute x = 3 into the simplified expression \( \frac{x^2 + 2x - 3}{x - 2} \) to find the limit.
The limit as x approaches 3 is the value of the function at x = 3, which is \( \frac{12}{1} = 12 \). Therefore, the limit is 12.