Suppose the product of two positive real numbers is . Which pair of numbers has the smallest possible sum?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
5. Graphical Applications of Derivatives
Applied Optimization
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A poster is set to have a total area of 1150 cm2, with 2-cm margins on the sides and the top, and a 3-cm margin at the bottom. What dimensions will maximize the printed area?

A
Width: 22.5 cm, Height: 51.2 cm
B
Width: 35.6 cm, Height: 32.3 cm
C
Width = 30.3 cm, Height = 37.9 cm
D
Width: 28.1 cm, Height: 41.0 cm

1
Start by defining the variables for the dimensions of the poster. Let the width of the entire poster be 'W' and the height be 'H'.
The printed area is the area inside the margins. Given the margins are 2 cm on the sides and top, and 3 cm at the bottom, the printed width is 'W - 4' and the printed height is 'H - 5'.
The total area of the poster is given as 1150 cm². Therefore, the equation for the total area is: W * H = 1150.
To maximize the printed area, express the printed area as a function of one variable using the constraint W * H = 1150. Substitute H = 1150/W into the printed area formula: Printed Area = (W - 4) * (1150/W - 5).
Find the derivative of the printed area function with respect to W, set it to zero, and solve for W to find the critical points. Use the second derivative test or analyze the critical points to determine which values of W maximize the printed area.
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