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Multiple Choice
Which of the following integrals is improper because the interval of integration is infinite?
A
B
C
D
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1
Step 1: Understand the definition of an improper integral. An integral is considered improper if it involves an infinite interval of integration or if the integrand becomes unbounded within the interval.
Step 2: Analyze each integral provided in the problem. For example, int_0^1 x^2 dx has a finite interval [0, 1] and the integrand x^2 is well-behaved (bounded) within this interval, so it is not improper.
Step 3: Examine int_1^2 sqrt{x} dx. The interval [1, 2] is finite, and the integrand sqrt{x} is also bounded within this interval, so this integral is not improper.
Step 4: Consider int_1^{infty} frac{1}{x^2} dx. The interval of integration is [1, ∞), which is infinite. This makes the integral improper due to the infinite upper limit of integration.
Step 5: Review int_{-1}^1 frac{1}{x} dx. The interval [-1, 1] is finite, but the integrand frac{1}{x} becomes unbounded at x = 0 (division by zero). This makes the integral improper due to the unbounded behavior of the integrand within the interval.