Express the integral as a limit of Riemann sums using right endpoints. Do not evaluate the limit.
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8. Definite Integrals
Riemann Sums
Problem 5.2.32d
Textbook Question
{Use of Tech} Approximating definite integrals Complete the following steps for the given integral and the given value of n.
(d) Determine which Riemann sum (left or right) underestimates the value of the definite integral and which overestimates the value of the definite integral..
β«βΒ² (πΒ²β2) dπ ; n = 4

1
Step 1: Understand the problem. The goal is to approximate the definite integral β«βΒ² (πΒ² - 2) dπ using Riemann sums with n = 4 subintervals. Additionally, determine which Riemann sum (left or right) underestimates or overestimates the integral.
Step 2: Divide the interval [0, 2] into n = 4 subintervals. The width of each subinterval, Ξπ, is calculated as Ξπ = (b - a) / n, where a = 0 and b = 2. This gives Ξπ = 2 / 4 = 0.5.
Step 3: For the left Riemann sum, use the left endpoints of each subinterval to evaluate the function f(π) = πΒ² - 2. The left endpoints are πβ = 0, πβ = 0.5, πβ = 1, and πβ = 1.5. Compute the sum as L = Ξπ * [f(πβ) + f(πβ) + f(πβ) + f(πβ)].
Step 4: For the right Riemann sum, use the right endpoints of each subinterval to evaluate the function f(π) = πΒ² - 2. The right endpoints are πβ = 0.5, πβ = 1, πβ = 1.5, and πβ = 2. Compute the sum as R = Ξπ * [f(πβ) + f(πβ) + f(πβ) + f(πβ)].
Step 5: Analyze the behavior of the function f(π) = πΒ² - 2 over the interval [0, 2]. Since the function is increasing on this interval, the left Riemann sum will underestimate the integral (as it uses lower values of the function), and the right Riemann sum will overestimate the integral (as it uses higher values of the function).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Riemann Sums
Riemann sums are a method for approximating the value of a definite integral by dividing the area under a curve into smaller rectangles. The sum of the areas of these rectangles provides an estimate of the integral's value. Depending on whether the left or right endpoints of the subintervals are used, the Riemann sum can either overestimate or underestimate the actual area, which is crucial for understanding the behavior of the integral.
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Introduction to Riemann Sums
Definite Integrals
A definite integral represents the signed area under a curve between two specified limits. It is denoted as β«βα΅ f(x) dx, where 'a' and 'b' are the lower and upper limits, respectively. The value of a definite integral can be interpreted as the accumulation of quantities, such as area, over an interval, making it essential for applications in physics, engineering, and economics.
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Definition of the Definite Integral
Underestimation and Overestimation
In the context of Riemann sums, underestimation occurs when the sum of the areas of the rectangles is less than the actual area under the curve, while overestimation occurs when the sum exceeds the actual area. For a function that is increasing on the interval, the left Riemann sum will underestimate the integral, and the right Riemann sum will overestimate it. Conversely, for a decreasing function, the opposite is true, highlighting the importance of the function's behavior in determining the accuracy of the approximation.
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Left, Right, & Midpoint Riemann Sums Example 1
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