Find the global maximum and minimum values of the function on the region defined by .
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
5. Graphical Applications of Derivatives
Finding Global Extrema
Multiple Choice
Which of the following points is a location where the function is discontinuous?
A
B
C
D
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Verified step by step guidance1
Step 1: Recall the definition of discontinuity. A function is discontinuous at a point if it is not defined at that point or if there is a break, jump, or infinite behavior in the graph of the function.
Step 2: Analyze the given function f(x) = . The denominator x - 2 must not be equal to zero because division by zero is undefined.
Step 3: Solve the equation x - 2 = 0 to find the value of x where the function is undefined. This gives x = 2.
Step 4: Check the other points provided in the options (x = 1, x = 0, x = 3). Substitute these values into the denominator x - 2 to verify that the function is defined at these points.
Step 5: Conclude that the function is discontinuous at x = 2 because the denominator becomes zero, making the function undefined at this point.
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