{Use of Tech} Height and time The height in feet of a baseball hit straight up from the ground with an initial velocity of 64 ft/s is given by h= ƒ(t) = 64t - 16t² where t is measured in seconds after the hit.
d. At what time is the ball at a height of 30 ft on the way up?
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Set the height function equal to 30: \( 64t - 16t^2 = 30 \).
Rearrange the equation to form a standard quadratic equation: \( -16t^2 + 64t - 30 = 0 \).
Simplify the equation by dividing all terms by -2: \( 8t^2 - 32t + 15 = 0 \).
Use the quadratic formula \( t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) where \( a = 8 \), \( b = -32 \), and \( c = 15 \).
Calculate the discriminant \( b^2 - 4ac \) and solve for \( t \) using the quadratic formula, selecting the solution that corresponds to the ball on the way up.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Quadratic Functions
The height function h(t) = 64t - 16t² is a quadratic function, which is a polynomial of degree two. Quadratic functions graph as parabolas, and their general form is ax² + bx + c. Understanding the properties of parabolas, such as their vertex and axis of symmetry, is essential for analyzing the height of the baseball over time.
To find the time when the baseball reaches a height of 30 ft, we need to solve the equation 64t - 16t² = 30. This involves rearranging the equation into standard form (16t² - 64t + 30 = 0) and applying methods such as factoring, completing the square, or using the quadratic formula. Mastery of these techniques is crucial for finding the roots of the equation.
Interpreting function values involves understanding what the output of a function represents in a real-world context. In this case, the function h(t) gives the height of the baseball at any time t. Recognizing that we are looking for specific instances when the height equals 30 ft helps in setting up the problem correctly and understanding the physical implications of the solution.