Evaluating integrals Evaluate the following integrals.
∫√₂/₅^²/⁵ d𝓍/𝓍√(25𝓍² ―1)
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Step 1: Recognize the integral's structure. The given integral involves a square root in the denominator and a term resembling the derivative of an inverse trigonometric function. Specifically, it resembles the form of an integral involving arcsine or arctangent.
Step 2: Simplify the denominator. Notice that the denominator is √(25𝓍² - 1). Factor out 25 from the square root to rewrite it as √(25(𝓍² - 1/25)). This simplifies the expression inside the square root.
Step 3: Perform a substitution. Let u = 𝓍, and rewrite the integral in terms of u. This substitution helps simplify the integral further and prepares it for evaluation using standard formulas.
Step 4: Identify the standard formula. The integral now resembles the form ∫ du / u√(a²u² - b²), which can be solved using the formula for inverse trigonometric functions. Specifically, it matches the form of an arcsine or arctangent integral.
Step 5: Apply the formula and adjust for constants. Use the appropriate inverse trigonometric formula, ensuring to account for the constants (like 25) introduced during simplification. After applying the formula, simplify the result and include the constant of integration.
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