14–25. {Use of Tech} Areas of regions Determine the area of the given region.
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
9. Graphical Applications of Integrals
Area Between Curves
Problem 6.5.23a
Textbook Question
21–30. {Use of Tech} Arc length by calculator
a. Write and simplify the integral that gives the arc length of the following curves on the given interval.
y = ln x, for 1≤x≤4

1
Recall the formula for the arc length of a curve given by a function \( y = f(x) \) on the interval \( [a, b] \):
$$ L = \int_a^b \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx $$
Identify the function and the interval: here, \( y = \ln x \) and the interval is \( 1 \leq x \leq 4 \).
Compute the derivative \( \frac{dy}{dx} \) of \( y = \ln x \):
$$ \frac{dy}{dx} = \frac{1}{x} $$
Substitute \( \frac{dy}{dx} \) into the arc length formula:
$$ L = \int_1^4 \sqrt{1 + \left(\frac{1}{x}\right)^2} \, dx = \int_1^4 \sqrt{1 + \frac{1}{x^2}} \, dx $$
Simplify the expression under the square root:
$$ \sqrt{1 + \frac{1}{x^2}} = \sqrt{\frac{x^2 + 1}{x^2}} = \frac{\sqrt{x^2 + 1}}{x} $$
So the integral becomes:
$$ L = \int_1^4 \frac{\sqrt{x^2 + 1}}{x} \, dx $$

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Arc Length Formula
The arc length of a curve y = f(x) from x = a to x = b is given by the integral ∫ from a to b of √(1 + (dy/dx)²) dx. This formula calculates the length of the curve by summing infinitesimal line segments along the curve.
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Arc Length of Parametric Curves
Derivative of the Natural Logarithm Function
For y = ln(x), the derivative dy/dx is 1/x. Understanding this derivative is essential to substitute into the arc length formula, as it determines the slope of the curve at each point.
Recommended video:
Derivative of the Natural Logarithmic Function
Simplifying the Integral Expression
After substituting dy/dx into the arc length formula, the integral often requires algebraic simplification before evaluation. Simplifying √(1 + (1/x)²) to √(1 + 1/x²) = √((x² + 1)/x²) = √(x² + 1)/x helps in setting up the integral for numerical or calculator-based evaluation.
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Simplifying Trig Expressions
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