Many formulas There are several ways to express the indefinite integral of sech x.
b. Show that ∫ sech x dx = sin⁻¹ (tanh x) + C. (Hint: Show that sech x = sech² x / √(1 − tanh² x) and then make a change of variables.)
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Start with the integral you want to solve: \(\int \text{sech}\,x \, dx\).
Use the hint to rewrite \(\text{sech}\,x\) as \(\frac{\text{sech}^2 x}{\sqrt{1 - \tanh^2 x}}\). So the integral becomes \(\int \frac{\text{sech}^2 x}{\sqrt{1 - \tanh^2 x}} \, dx\).
Recognize that the derivative of \(\tanh x\) is \(\text{sech}^2 x\), which suggests the substitution \(u = \tanh x\). Then, \(du = \text{sech}^2 x \, dx\).
Rewrite the integral in terms of \(u\): it becomes \(\int \frac{1}{\sqrt{1 - u^2}} \, du\).
Recall that \(\int \frac{1}{\sqrt{1 - u^2}} \, du = \sin^{-1} u + C\). Substitute back \(u = \tanh x\) to get the final expression: \(\sin^{-1}(\tanh x) + C\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Hyperbolic Functions and Their Identities
Hyperbolic functions like sech x and tanh x are analogs of trigonometric functions but based on exponential definitions. Understanding identities such as 1 - tanh² x = sech² x is crucial for manipulating expressions and simplifying integrals involving these functions.
The substitution method involves changing variables to simplify an integral. By expressing the integral in terms of a new variable (e.g., u = tanh x), the integral becomes easier to evaluate, often transforming complicated expressions into standard forms.
Inverse functions like sin⁻¹ and tanh⁻¹ help express antiderivatives in closed form. Recognizing when an integral corresponds to an inverse trigonometric function, such as sin⁻¹(tanh x), allows for correct evaluation and interpretation of indefinite integrals.