Provide a short answer to each question. What is the equation of the vertical asymptote of the graph of y=1/(x-3)+2? Of the horizontal asymptote?

A vertical asymptote occurs in a rational function when the denominator approaches zero, causing the function to approach infinity. For the function y = 1/(x-3) + 2, the vertical asymptote is found by setting the denominator equal to zero, which gives x = 3. This means that as x approaches 3, the value of y will increase or decrease without bound.

A horizontal asymptote describes the behavior of a function as x approaches infinity or negative infinity. For rational functions, if the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y = 0. In the case of y = 1/(x-3) + 2, as x approaches infinity, the term 1/(x-3) approaches 0, leading to a horizontal asymptote at y = 2.

Rational functions are expressions formed by the ratio of two polynomials. They can exhibit unique behaviors such as asymptotes, which are lines that the graph approaches but never touches. Understanding the structure of rational functions is essential for analyzing their graphs, including identifying vertical and horizontal asymptotes, which are critical for sketching the function accurately.