Solve each equation. See Example 1. (2x+5)/2 - 3x/(x-2) = x

Question

Accepted Answer

For the following equation solved for X three expose 13/3 minus five, X over four, X minus one is equal to X. So you want to solve for X. The first thing we can do is actually multiply both sides by the L C D. I'll see these at least comes denominator Which we can multiply. Our two denominators are fashions together to get this three times X -1. I'm gonna multiply everything by this L C D, the X plus 13/3 -5 X over four X -1. It's A X, we're multiplying by L C D three times 4 x -1, three times works -1 and we do the same thing on the right side like so Now look, here are threes will cancel, giving us three x plus 13 Times four x - and our four X minus one is canceled here giving us negative five X times three Right side. We have three x times four X -1. Now we can simplify even more three x times four x 12 x squared three X 9 to 1 to three X 13 test four X 52 X apparently 13 times negative one negative 13, five X times 3 to 15 X. This is equal to three X times four X 12 X squared and three X times negative one negative three X. Now we can simplify even more. That's everything from the right side over first add toilet squared and add three X. So I subtract 12 X squared grounds not add, subtract. So you have to subtract that Manage toilet squared plus three x. Those cancel giving us 52 x -13 -15 x is equal to zero. We can simplify 52 and 15 to give us 37 x -13 equal to zero. Then we moved 13 over You have 37 x is equal to 13. Finally divided by 37 gives us X is equal to 13/37. We cannot simplify this any more. So the answer to our problem turns out to be answer B okay. I have to help you solve the problem. Thank you for watching. Goodbye.

Solve each equation. See Example 1. (2x+5)/2 - 3x/(x-2) = x

Key Concepts

Solving Rational Equations

Finding the Least Common Denominator (LCD)

Checking for Extraneous Solutions

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