Identify the oxidation and reduction half-reactions. In this case, ClO⁻ is reduced to Cl⁻, and Cr(OH)₃ is oxidized to CrO₄²⁻.
Write the half-reactions separately. For reduction: ClO⁻ → Cl⁻. For oxidation: Cr(OH)₃ → CrO₄²⁻.
Balance each half-reaction for mass and charge. Add water (H₂O) to balance oxygen atoms and hydroxide ions (OH⁻) to balance hydrogen atoms in a basic solution.
Combine the balanced half-reactions, ensuring that the electrons lost in the oxidation half-reaction equal the electrons gained in the reduction half-reaction.
Verify that the final equation is balanced for both mass and charge, and that it matches one of the given options.