Identify the reactants and products in the given reaction: sodium chloride (NaCl) and mercury(I) acetate (Hg2(C2H3O2)2) react to form sodium acetate (NaC2H3O2) and mercury(I) chloride (Hg2Cl2).
Write the unbalanced chemical equation with correct formulas: \(\mathrm{NaCl(aq) + Hg_2(C_2H_3O_2)_2(aq) \rightarrow NaC_2H_3O_2(aq) + Hg_2Cl_2(s)}\).
Balance the mercury(I) species: since there is one Hg2 unit on both sides, mercury is already balanced.
Balance the acetate (C2H3O2) and sodium (Na) ions: mercury(I) acetate has two acetate groups, so to balance acetate and sodium on the product side, multiply sodium acetate by 2, giving \(2\ \mathrm{NaC_2H_3O_2}\).
Balance the chloride ions: since 2 moles of NaCl provide 2 chloride ions, and Hg2Cl2 contains 2 chloride ions, multiply NaCl by 2 to balance chlorides, resulting in the balanced equation: \(2\ \mathrm{NaCl(aq) + Hg_2(C_2H_3O_2)_2(aq) \rightarrow 2\ NaC_2H_3O_2(aq) + Hg_2Cl_2(s)}\).