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Multiple Choice
How many electrons are present in the outer (valence) shell of an Al^{3+} ion?
A
1
B
0
C
8
D
3
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Verified step by step guidance
1
Identify the atomic number of aluminum (Al), which is 13. This means a neutral Al atom has 13 electrons.
Determine the electron configuration of a neutral Al atom. The configuration is \$1s^2 2s^2 2p^6 3s^2 3p^1$.
Recognize that the outer (valence) shell for aluminum is the third shell, containing the electrons in the \$3s\( and \)3p$ orbitals, totaling 3 valence electrons.
Consider the charge of the ion, Al\(^{3+}\), which means the atom has lost 3 electrons. These electrons are removed from the outermost shell first.
Subtract the 3 lost electrons from the 3 valence electrons, resulting in zero electrons remaining in the outer shell of the Al\(^{3+}\) ion.