Open Question
When a radioactive isotope releases a beta particle, the atomic number of the new element is
528
views
21. Nuclear Chemistry
Beta Decay
Struggling with General Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Which of the following represents the balanced nuclear equation for the beta minus (β−) decay of cobalt-60 (Co-60)?
A
^{60}_{27}Co \rightarrow ^{60}_{28}Ni + e^{-} + \overline{\nu}_e
B
^{60}_{27}Co \rightarrow ^{59}_{28}Ni + n
C
^{60}_{27}Co \rightarrow ^{60}_{27}Co + \gamma
D
^{60}_{27}Co \rightarrow ^{60}_{26}Fe + e^{+} + \nu_e
Verified step by step guidance1
Understand that beta minus (β⁻) decay involves the transformation of a neutron into a proton within the nucleus, emitting an electron (beta particle) and an antineutrino.
Write the general form of beta minus decay: \(^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + e^{-} + \overline{\nu}_e\), where the mass number \(A\) remains the same, and the atomic number \(Z\) increases by 1.
Apply this to cobalt-60, which has \(A=60\) and \(Z=27\). After beta minus decay, the new element will have \(A=60\) and \(Z=28\), which corresponds to nickel (Ni).
Check that the emitted particles include an electron (\(e^{-}\)) and an antineutrino (\(\overline{\nu}_e\)) to conserve charge and lepton number.
Confirm that the balanced nuclear equation is \(^{60}_{27}Co \rightarrow ^{60}_{28}Ni + e^{-} + \overline{\nu}_e\), ensuring conservation of both mass number and atomic number.
Related Videos
Related Practice
