Multiple Choice
A sample of glucose (C6H12O6) has a molar mass of 180.16 g/mol. What is the percent composition of carbon in glucose?
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3. Chemical Reactions
Mass Percent
Multiple Choice
What is the mass percent of fluorine in carbon tetrafluoride (CF_4)?
A
63.5%
B
86.4%
C
13.6%
D
50.0%
Verified step by step guidance1
Identify the chemical formula of the compound: carbon tetrafluoride is CF_4, which means it contains 1 carbon atom and 4 fluorine atoms.
Find the atomic masses of each element from the periodic table: carbon (C) has an atomic mass of approximately 12.01 g/mol, and fluorine (F) has an atomic mass of approximately 18.998 g/mol.
Calculate the total molar mass of CF_4 by adding the atomic mass of carbon and four times the atomic mass of fluorine: \(M_{CF_4} = M_C + 4 \times M_F\).
Calculate the total mass of fluorine in one mole of CF_4 by multiplying the atomic mass of fluorine by 4: \(M_F^{total} = 4 \times M_F\).
Determine the mass percent of fluorine in CF_4 using the formula: \(\text{Mass \% of F} = \left( \frac{M_F^{total}}{M_{CF_4}} \right) \times 100\%\).
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