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Multiple Choice
Which ions are formed when MgI_2 dissociates in water?
A
Mg^{2+} and 2 I^{-}
B
Mg^{2-} and 2 I^{+}
C
Mg^{+} and 2 I^{+}
D
Mg^{2+} and 2 I^{2-}
Verified step by step guidance
1
Identify the compound given: MgI_2, which is magnesium iodide.
Recall that magnesium (Mg) is a metal from Group 2 of the periodic table and typically forms a cation with a charge of +2, written as $Mg^{2+}$.
Iodine (I) is a halogen and typically forms an anion with a charge of -1, written as $I^{-}$.
Since the formula is MgI_2, one magnesium ion pairs with two iodide ions to balance the charges, resulting in $Mg^{2+}$ and 2 $I^{-}$ ions upon dissociation.
Write the dissociation equation in water as: $MgI_2 (s) \rightarrow Mg^{2+} (aq) + 2 I^{-} (aq)$.