Multiple Choice
What is the molarity of a solution prepared by dissolving 52.0 g of glucose (C6H12O6) in enough water to make 0.750 L of solution?
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6. Chemical Quantities & Aqueous Reactions
Molarity
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How many grams of KNO3 are required to prepare 250. mL of a 0.135 M solution?
A
1.70 g
B
0.90 g
C
3.41 g
D
5.10 g
Verified step by step guidance1
Identify the given information: volume of solution (V) = 250. mL, molarity (M) = 0.135 M, and the solute is KNO\_3.
Convert the volume from milliliters to liters because molarity is expressed in moles per liter: \(V(\text{L}) = \frac{250.\ \text{mL}}{1000}\).
Use the molarity definition to find the number of moles of KNO\_3 needed: \(\text{moles} = M \times V(\text{L})\).
Calculate the molar mass of KNO\_3 by adding the atomic masses of K, N, and O (potassium, nitrogen, and oxygen respectively).
Convert moles of KNO\_3 to grams using the molar mass: \(\text{mass} = \text{moles} \times \text{molar mass}\).
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