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Multiple Choice
A 100 g sample of water at 25 °C is cooled to 0 °C. How much energy must be transferred out of the system as heat (q) to lower its temperature to 0 °C? (Specific heat capacity of water = 4.18 J/g·°C)
A
1,045 J
B
418 J
C
10,450 J
D
2,500 J
Verified step by step guidance
1
Identify the known values from the problem: mass of water (m) = 100 g, initial temperature (T_i) = 25 °C, final temperature (T_f) = 0 °C, and specific heat capacity (c) = 4.18 J/g·°C.
Calculate the temperature change (\Delta T) using the formula: \(\Delta T = T_f - T_i\).
Use the formula for heat transfer: \(q = m \times c \times \Delta T\), where \(q\) is the heat energy transferred.
Substitute the known values into the formula: \(q = 100 \text{ g} \times 4.18 \text{ J/g·°C} \times (0 - 25) \text{ °C}\).
Calculate the product to find the amount of energy transferred out of the system as heat (note that the result will be negative, indicating heat loss).