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Multiple Choice
Which compound will be more soluble in the solvent CH3OCH3 (diethyl ether), and why: HCl(g) or NaCl(s)?
A
NaCl(s), because it forms hydrogen bonds with diethyl ether.
B
NaCl(s), because ionic compounds are always more soluble in organic solvents.
C
HCl(g), because it is a polar molecule and can interact with the polar ether solvent.
D
Both HCl(g) and NaCl(s) are equally soluble in CH3OCH3.
Verified step by step guidance
1
Step 1: Identify the nature of the solvent CH3OCH3 (diethyl ether). Diethyl ether is a polar aprotic solvent, meaning it has a dipole moment but does not have hydrogen atoms bonded to highly electronegative atoms (like O-H or N-H) to form hydrogen bonds as a donor.
Step 2: Analyze the solutes: HCl(g) is a polar covalent molecule with a dipole moment, while NaCl(s) is an ionic compound composed of Na+ and Cl- ions.
Step 3: Consider the solubility principle 'like dissolves like,' which means polar solvents tend to dissolve polar molecules, and ionic compounds generally dissolve better in polar protic solvents (like water) that can stabilize ions through ion-dipole interactions and hydrogen bonding.
Step 4: Evaluate interactions: HCl, being polar, can interact with the dipole of diethyl ether through dipole-dipole interactions, enhancing its solubility. NaCl, being ionic, requires strong ion-dipole interactions and often hydrogen bonding from the solvent to dissolve well, which diethyl ether cannot provide effectively.
Step 5: Conclude that HCl will be more soluble in diethyl ether because it is a polar molecule compatible with the polar solvent, whereas NaCl's ionic nature makes it poorly soluble in diethyl ether due to lack of strong ion-dipole or hydrogen bonding interactions.