Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

6. Chemical Quantities & Aqueous Reactions

Solubility Rules

General Chemistry

6. Chemical Quantities & Aqueous Reactions

Solubility Rules

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Multiple Choice

Which of the following salts has the highest molar solubility in water at room temperature?

AgCl

NaNO_3

CaCO_3

BaSO_4

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Verified step by step guidance

Understand that molar solubility refers to the number of moles of a salt that can dissolve in a liter of water to form a saturated solution at a given temperature.

Recall that the solubility of ionic salts in water depends on their solubility product constant, $K_{sp}$, which quantifies the extent to which the salt dissociates into its ions in solution.

Recognize that salts like NaNO$_3$ are generally highly soluble because they dissociate completely into ions (Na$^+$ and NO$_3^-$) and have very large $K_{sp}$ values, effectively making their solubility limited only by the amount added.

Compare the $K_{sp}$ values of the other salts (AgCl, CaCO$_3$, BaSO$_4$), which are known to be sparingly soluble salts with much smaller $K_{sp}$ values, indicating lower molar solubility.

Conclude that the salt with the highest molar solubility is the one with the largest $K_{sp}$ or that is known to be highly soluble, which in this case is NaNO$_3$.