Multiple Choice
Which statement best describes how the polarity of a solute affects its solubility in a solvent?
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6. Chemical Quantities & Aqueous Reactions
Solubility Rules
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At 20 °C, the solubility of NaNO3 in water is approximately 88 g per 100 g of water. If 100 g of NaNO3 is added to 100 g of water at 20 °C, how many grams of NaNO3 will remain dissolved in the solution?
A
50 g
B
88 g
C
12 g
D
100 g
Verified step by step guidance1
Identify the solubility of NaNO3 at 20 °C, which is given as 88 g of NaNO3 per 100 g of water. This means that at this temperature, a maximum of 88 g of NaNO3 can dissolve in 100 g of water to form a saturated solution.
Note the amount of NaNO3 added to the water: 100 g of NaNO3 is added to 100 g of water. Since the solubility limit is 88 g per 100 g water, adding more than 88 g means not all of the NaNO3 will dissolve.
Determine the amount of NaNO3 that will remain dissolved by comparing the amount added to the solubility limit. The maximum dissolved amount is the solubility value, which is 88 g.
Calculate the amount of NaNO3 that will remain undissolved by subtracting the solubility limit from the amount added: 100 g (added) - 88 g (dissolved) = 12 g undissolved.
Conclude that the amount of NaNO3 dissolved in the solution at 20 °C is 88 g, and the rest (12 g) remains undissolved as a solid.
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