Multiple Choice
For the principal quantum number n = 4, how many possible combinations are there for the values of the angular momentum quantum number l and the magnetic quantum number ml?
75
views
9. Quantum Mechanics
Quantum Numbers: Angular Momentum Quantum Number
Multiple Choice
For a principal quantum number n = 3, what is the full range of possible values for the angular momentum quantum number l?
A
0, 1, 2, 3
B
0, 1, 2
C
1, 2
D
1, 2, 3
Verified step by step guidance1
Recall that the principal quantum number \(n\) determines the energy level or shell of an electron in an atom, and it must be a positive integer (\(n = 1, 2, 3, \ldots\)).
Understand that the angular momentum quantum number \(l\) defines the shape of the orbital and can take on integer values from \$0\( up to \)n-1\( for a given principal quantum number \)n$.
For \(n = 3\), list all possible values of \(l\) by applying the rule \(l = 0, 1, 2, \ldots, (n-1)\), which means \(l\) can be \$0\(, \)1\(, or \)2$.
Recognize that \(l = 3\) is not possible for \(n = 3\) because \(l\) cannot be equal to or greater than \(n\).
Therefore, the full range of possible values for \(l\) when \(n = 3\) is \$0\(, \)1\(, and \)2$.
Related Videos
Related Practice
