Join thousands of students who trust us to help them ace their exams!
Multiple Choice
Which of the following is the correct Lewis electron dot structure for neutral magnesium chloride (MgCl_2)?
A
Mg^{2+} [ :Cl: ] [ :Cl: ]
B
Mg [ :Cl: ] [ :Cl: ]
C
Mg^{2+} [ :Cl: ]^{-} [ :Cl: ]^{-}
D
Mg [ :Cl: ]^{-} [ :Cl: ]^{-}
0 Comments
Verified step by step guidance
1
Step 1: Identify the nature of bonding in magnesium chloride (MgCl_2). Magnesium is a metal and chlorine is a nonmetal, so MgCl_2 is an ionic compound formed by the transfer of electrons from magnesium to chlorine atoms.
Step 2: Determine the electron configuration changes. Magnesium (Mg) starts with 2 valence electrons and tends to lose both to achieve a stable noble gas configuration, becoming Mg^{2+}. Each chlorine atom (Cl) needs one electron to complete its octet, so each Cl gains one electron, becoming Cl^{-}.
Step 3: Draw the Lewis structure for the ions. Represent Mg as Mg^{2+} with no dots around it because it has lost its valence electrons. Each Cl^{-} should be shown with 8 dots (4 pairs) around the symbol to represent the full octet, and a negative charge to indicate the extra electron.
Step 4: Combine the ions to form the neutral compound. Since Mg^{2+} has a +2 charge and each Cl^{-} has a -1 charge, two Cl^{-} ions balance the charge of one Mg^{2+} ion, resulting in a neutral MgCl_2 compound.
Step 5: Verify the overall charge and octet completion. Ensure that the Mg ion has no valence electrons (due to loss) and each Cl ion has a complete octet with a negative charge, confirming the correct Lewis electron dot structure is Mg^{2+} [ :Cl: ]^{-} [ :Cl: ]^{-}.