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Multiple Choice
Which of the following is the correct chemical formula for lead(IV) sulfate?
A
Pb2(SO4)4
B
PbSO4
C
Pb(SO4)2
D
Pb2SO4
Verified step by step guidance
1
Identify the oxidation state of lead in lead(IV) sulfate. The Roman numeral IV indicates that lead has a +4 charge (Pb^{4+}).
Determine the charge of the sulfate ion. Sulfate (SO_4) has a charge of -2 (SO_4^{2-}).
Balance the total positive and negative charges to form a neutral compound. Since Pb^{4+} has a +4 charge and SO_4^{2-} has a -2 charge, two sulfate ions are needed to balance one lead ion: +4 from Pb and 2 × (-2) = -4 from sulfate.
Write the chemical formula by placing the lead ion first, followed by the sulfate ion with the appropriate subscript to indicate quantity: Pb(SO_4)_2.
Verify that the total charge is zero by multiplying the charge of each ion by its subscript and confirming they sum to zero: (1 × +4) + (2 × -2) = 0.