Understand that breaking chemical bonds requires energy input, so the enthalpy change (\(\triangle\) H) for bond breaking is positive (\(\triangle\) H > 0).
Look at each given reaction and identify whether bonds are being formed or broken by analyzing the reactants and products.
For the reaction \( \mathrm{CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g)} \) with \( \triangle H < 0 \), note that the negative enthalpy indicates bond formation (energy released), not bond breaking.
For the reaction \( \mathrm{NaCl(s) \rightarrow Na^+(aq) + Cl^-(aq)} \) with \( \triangle H < 0 \), the negative enthalpy suggests energy is released, indicating bond formation or solvation, not bond breaking.
For the reaction \( \mathrm{H_2(g) \rightarrow 2H(g)} \) with \( \triangle H > 0 \), recognize that the bond in \( \mathrm{H_2} \) is being broken into atoms, which requires energy absorption, matching the condition for bond breaking.