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Multiple Choice
What is the mass percent of oxygen in sodium carbonate (Na2CO3)?
A
48.0%
B
30.4%
C
16.0%
D
53.0%
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Verified step by step guidance
1
Identify the chemical formula of sodium carbonate, which is \(\mathrm{Na_2CO_3}\), and note the elements present: sodium (Na), carbon (C), and oxygen (O).
Determine the atomic masses of each element from the periodic table: sodium (Na) approximately 23 g/mol, carbon (C) approximately 12 g/mol, and oxygen (O) approximately 16 g/mol.
Calculate the molar mass of sodium carbonate by summing the contributions of each element: \(2 \times 23\) for sodium, \(1 \times 12\) for carbon, and \(3 \times 16\) for oxygen. Express this as \(M_{\mathrm{Na_2CO_3}} = 2(23) + 12 + 3(16)\).
Calculate the total mass of oxygen atoms in one mole of sodium carbonate, which is \(3 \times 16\) g.
Find the mass percent of oxygen by dividing the total mass of oxygen by the molar mass of sodium carbonate and multiplying by 100%, using the formula: \(\text{Mass \% O} = \frac{3 \times 16}{M_{\mathrm{Na_2CO_3}}} \times 100\%\).