Multiple Choice
When 44 grams of propane (C_3H_8) are completely combusted in excess oxygen, how many grams of water (H_2O) are produced?
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3. Chemical Reactions
Stoichiometry
Multiple Choice
How many atoms of sulfur are present in 4.30 grams of carbon disulfide (CS_2)?
A
2.16 × 10^{23} atoms
B
1.08 × 10^{23} atoms
C
3.61 × 10^{22} atoms
D
6.02 × 10^{22} atoms
Verified step by step guidance1
Identify the molecular formula of carbon disulfide, which is CS\_2, meaning each molecule contains 2 atoms of sulfur.
Calculate the molar mass of CS\_2 by adding the atomic masses: Carbon (C) is approximately 12.01 g/mol and Sulfur (S) is approximately 32.07 g/mol. So, molar mass = 12.01 + 2 \(\times\) 32.07 g/mol.
Determine the number of moles of CS\_2 in 4.30 grams by using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\).
Calculate the total number of molecules of CS\_2 by multiplying the moles by Avogadro's number (\(6.022 \times 10^{23}\) molecules/mol): \(\text{molecules} = \text{moles} \times 6.022 \times 10^{23}\).
Since each molecule contains 2 sulfur atoms, multiply the total number of molecules by 2 to find the total number of sulfur atoms: \(\text{S atoms} = 2 \times \text{molecules}\).
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