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Multiple Choice
Given that air is approximately 21% oxygen by mole, how many moles of propane (C_3H_8) are needed to completely react with the oxygen present in 24.0 moles of air?
A
5.04 moles
B
0.70 moles
C
2.86 moles
D
1.71 moles
Verified step by step guidance
1
Write the balanced chemical equation for the combustion of propane (C\_3H\_8):
\[ C\_3H\_8 + 5O\_2 \rightarrow 3CO\_2 + 4H\_2O \]
Determine the moles of oxygen (O\_2) present in 24.0 moles of air, knowing that air is approximately 21% oxygen by mole:
\[ \text{moles of } O\_2 = 0.21 \times 24.0 \]
Use the stoichiometric ratio from the balanced equation to relate moles of oxygen to moles of propane. According to the equation, 1 mole of propane reacts with 5 moles of oxygen:
\[ \text{moles of } C\_3H\_8 = \frac{\text{moles of } O\_2}{5} \]
Substitute the moles of oxygen calculated in step 2 into the equation from step 3 to find the moles of propane needed to react completely with the oxygen in 24.0 moles of air.
Interpret the result as the amount of propane required for complete combustion with the oxygen available in the given amount of air.