Multiple Choice
In the complex ion [Fe(SCN)6]^{3-}, what is the molar ratio of Fe^{3+} ions to [Fe(SCN)6]^{3-} ions?
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3. Chemical Reactions
Stoichiometry
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What volume (in L) of 1.60 M Na3PO4 solution is required to obtain 0.600 moles of Na+ ions?
A
0.375 L
B
0.125 L
C
0.200 L
D
0.600 L
Verified step by step guidance1
Identify the number of moles of Na+ ions provided by one mole of Na3PO4. Since Na3PO4 dissociates into 3 Na+ ions and 1 PO4^{3-} ion, each mole of Na3PO4 provides 3 moles of Na+ ions.
Set up the relationship between moles of Na+ ions and moles of Na3PO4: \( \text{moles of Na+} = 3 \times \text{moles of Na3PO4} \). Rearrange to find moles of Na3PO4: \( \text{moles of Na3PO4} = \frac{\text{moles of Na+}}{3} \).
Calculate the moles of Na3PO4 needed to get 0.600 moles of Na+ ions using the formula from step 2.
Use the molarity definition to relate moles of Na3PO4 to volume of solution: \( M = \frac{\text{moles of solute}}{\text{volume in liters}} \). Rearrange to find volume: \( V = \frac{\text{moles of solute}}{M} \).
Substitute the moles of Na3PO4 calculated in step 3 and the molarity (1.60 M) into the volume formula from step 4 to find the required volume of Na3PO4 solution.
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