Multiple Choice
How many atoms of hydrogen (H) are present in 200 molecules of ammonia (NH_3)?
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Table of contents
- 1. Intro to General Chemistry3h 48m
- Classification of Matter18m
- Physical & Chemical Changes19m
- Chemical Properties7m
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- Intensive vs. Extensive Properties13m
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- 2. Atoms & Elements4h 16m
- The Atom9m
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- The Alkyl Groups9m
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- 23. Chemistry of the Nonmetals2h 39m
- Main Group Elements: Bonding Types4m
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- 24. Transition Metals and Coordination Compounds3h 16m
- Atomic Radius & Density of Transition Metals11m
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- Ligands10m
- Complex Ions5m
- Coordination Complexes7m
- Classification of Ligands11m
- Coordination Numbers & Geometry9m
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- Isomerism in Coordination Complexes14m
- Orientations of D Orbitals4m
- Intro to Crystal Field Theory10m
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- Crystal Field Theory: Square Planar Complexes4m
- Crystal Field Theory Summary8m
- Magnetic Properties of Complex Ions9m
- Strong-Field vs Weak-Field Ligands6m
- Magnetic Properties of Complex Ions: Octahedral Complexes11m
2. Atoms & Elements
Mole Concept
Struggling with General Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
How many moles of KI are required to prepare 0.50 L of a 0.20 M aqueous solution?
A
0.10 mol
B
0.05 mol
C
0.20 mol
D
0.40 mol
Verified step by step guidance1
Identify the formula relating molarity (M), moles of solute (n), and volume of solution (V): \(M = \frac{n}{V}\).
Rearrange the formula to solve for moles of solute: \(n = M \times V\).
Substitute the given values into the equation: \(M = 0.20\, \text{mol/L}\) and \(V = 0.50\, \text{L}\).
Calculate the moles of KI needed by multiplying the molarity by the volume: \(n = 0.20 \times 0.50\).
Interpret the result as the number of moles of KI required to prepare the solution.
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