Join thousands of students who trust us to help them ace their exams!
Multiple Choice
What is the equilibrium constant expression for the reaction Fe(OH)3(s) + C2O42− ⇌ [Fe(C2O4)3]3−(aq) + OH−?
A
K_eq = [Fe(C2O4)3]3−[OH−]/[C2O42−]
B
K_eq = [Fe(C2O4)3]3−[OH−]
C
K_eq = [Fe(C2O4)3]3−/[OH−]
D
K_eq = [Fe(C2O4)3]3−[OH−][Fe(OH)3]
0 Comments
Verified step by step guidance
1
Identify the phases of each species in the reaction. Fe(OH)3 is a solid, C2O42− is an aqueous ion, [Fe(C2O4)3]3− is an aqueous complex, and OH− is an aqueous ion.
Recall that the equilibrium constant expression, K_eq, only includes species in the aqueous or gaseous phase. Solids and pure liquids are not included in the expression.
Write the general form of the equilibrium constant expression: K_eq = [products] / [reactants].
Apply the rule from step 2 to exclude Fe(OH)3 from the expression since it is a solid.
Construct the equilibrium constant expression: K_eq = [Fe(C2O4)3]3−[OH−] / [C2O42−].