What is the oxidation state of each element in K 2 Cr 2 O 7 ?

Hello everyone today. We are being asked the following question, calculate the oxidation number of iron in potassium ferret. So the first thing we do is we want to make take into account how many of each atom or element we have. So this potassium here, we have two of them and potassium because it is a group one a elements it has a positive one charge And then we have oxygen here and it is not a peroxide or a super oxide. So it has a charge of -2. We're then gonna set this equation of algebraic lee to solve for iron and iron in this situation is going to be represented by the variable X. So we said that we had to potassium. So we're gonna have to we're gonna multiply by its charge positive one. We're gonna add the we're gonna add X as the iron. And then we're going to add our oxygen. And so we have four oxygen's with the charge of negative two And we're gonna equal that to zero. And when we solve for X we're going to get that X is equal to positive six. And that will be our charge for iron overall. I hope this helped. And until next time